It is found that at
least 2-3 questions are given to calculate AVERAGE based questions in SSC IBPS
or other exam format. These questions are very easy to solve by using SIMPLE TRICKS
in 2-3 Seconds after reading statement of question.

These FASTEST AVERAGE
TRICKS helps in getting CUT-OFF score in exams. Use these tricks to solve NUMERICAL
ABILIY section of SSC IBPS or other any other competitive exam.

**FASTEST AVERAGE TRICKS are described as follows:**

1.
AVERAGE = Sum of numbers
/ Total numbers

2.
If the AVERAGE of n
number is m, then SUM of n numbers = mn

3.
In case of Age
calculation questions, if AVERAGE of age of n persons is x before (ago) m years,
then the SUM of age of n persons = n(x + m) to get present age of the group.

4.
AVERAGE = Sum of First &
Last number / 2

5.
AVERAGE = Sum of Middle
Terms / 2

6.
AVERAGE of Multiple of
Any number = Sum of First & Last Number / 2

7.
AVERAGE of first n
natural numbers = (n+1) / 2

8.
AVERAGE of first n consecutive
n even numbers = (n + 1)

9.
AVERAGE of first n consecutive
n odd numbers = n

10.
AVERAGE of square of
first n natural numbers = [n(n+1)(2n+1)] / 6

11.
AVERAGE of cubes of
first n natural numbers = [n(n+1) / 2]^{2}

12.
SUM of 1-100 natural
numbers = n (n-1) / 2

13.
SUM of First n ODD
numbers = n^{2}

14.
Geometric Mean (G. M.) of
any numbers x, y, z = ^{3}√*x.y.z*

15.
Harmonic Mean (H. M.) of
any numbers x, y, z = 1 / [1/3(1/x+1/y+1/z)]. Here 3 is the total number of
which H. M. is to be calculated which can be changed if more than 3 numbers are
used to calculate H. M. say if 4 numbers then it will become 4 & 5 for 5
and so-on.

16.
If any person covers
some distance in two parts with two different speeds. If he covers first part at
a speed of S_{1} km/hr and second part at a distance of S_{2}
km/hr, then AVERAGE speed during to cover the complete distance = 2 S_{1} S_{2 }/ _{ }(S_{1 }+ S_{2})

17.
In case if the same
person covers the whole journey in three different parts with different speeds S_{1
}, S_{2} and_{ }S_{3} then AVERAGE speed = 3 S_{1
}S_{2 }S_{3} / (S_{1} S_{2} + S_{2}
S_{3} + S_{3} S_{1})

18.
If AVERAGE of any n persons/items
is increased by x then the increased AVERAGE = nx

**Question 1:**

The average age of 10
persons in a committee is increased by 1 year. When two men age of 42 years and
38 years are replaced by two women. Find the average age of these women.

**Solution:**

**By using TRICK 18 (above),**

The Total average age of
n=10 persons increase age of m=1 year = 10x1 = 10 years.

Then Total age of two
men go out from the group = 42 + 38 = 80 years

Total age of two women
enters into group = 80 + 10 = 90

Then average age of these
women = 90 / 2 = 45years each

**Question 2:**

The average age of
husband and wife was 23 years when they got married 5 years ago. The age of
husband, wife and children who was born during the interval is 20years now. How
old is child now.

**Solution:**

**By using TRICK 3 (above)**

5 years Ago average age
of Husband + Wife = 23 years

Present Average age of
Husband + Wife = 23+5 = 28 years

Sum of Present age of Husband
+ Wife = 28 x 2 = 56 year

Similarly Sum of Present
age of Husband + Wife + Child = 20 x 3 = 60.

Thus the age of Child

= (Sum of Present age of
Husband + Wife + Child) - Sum of Present age of Husband + Wife)

= 60-56 = 4 years

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