**Math Short Cut Tricks to solve Time and Distance Problems - ****CRACK MATH-SCORE EXAM-TOP 7 TRICKS TO SOLVE TIME AND DISTANCE-FASTEST TRICK TO SOLVE MATH TIME AND DISTANCE PROBLEM-www.cutoffmarksresults.in**

It is found that at least 1-2 questions are given to calculate train speed, length and time in SSC IBPS or other exam format. These questions are very easy to solve by using top 7 tricks.

These Math Short Cut Tricks to solve Time and Distance Problems help in getting cracking score in exams. Remember these top 7 trick to solve any question related to calculate Train speed, length and time in any of the competitive exam.
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**Math Short Cut Tricks to solve Time and Distance Problems**
Top 7 tricks to solve Train speed and length question which are given
as follows:
1.
Average Speed = Total
Distance/Total Time

2.
Trick for Train
Questions:

**1 Km/hr = (All Lengths in meters x 18)/ (Time in seconds x 5)**

·
Let speed of Train in
Km/hr is to be found.

·
Put all distances in ‘All
Length in meters’ place (given for train or platform-Add all lengths in meter).

·
Put all time in ‘Time in
second’ place (covert all time to seconds-Add all Time).

·
Put all values and
calculate for answer.

3.
If a train is passing men,
car, bus, pole etc. then only Length of the train in meter will be considered.
It means no distance is taken for these objects. It means train passes and the
length calculated is the length for train only.

4.
If the train passes
bridge, tunnel, platform or another train, the distance will be added.

·
All Lengths in meters =
Length of the train + Length of the platform

·
All Lengths in meters =
Length of the train + Length of the Cave

·
All Lengths in meters =
Length of the train + Length of the Flyover

·
Whenever two distance
are provided in the question paper i.e. length of train, platform, cave,
flyover etc., then add these lengths and convert it into meters if it is given
in Kilometer, centimeter etc.

5.
When two train’s starts
from same platform in same direction to destinations with two different speeds,
then average speed will be subtraction between their speeds.

Let First train speed is
x m/s and other y m/s, then average speed will be x-y.

6.
When two trains starts
from same platform but in opposite direction, then average speed will be
addition of their speeds.

Let First train speed is
x m/s and other y m/s, then average speed will be x+y.

7.
Conversion:

·
1 Km/hr = 5/18 m/s (if
higher value is need-Km/hr then multiply with lower value-5/18 to m/s).

·
1 m/s = 18/5 Km/hr(if lower
value is need-m/s then multiply with higher value-18/5 to m/s).

__HOW TO APPLY TRAIN TRICKS - ____Math Short Cut Tricks to solve Time and Distance Problems__

**TYPE-1**

**Question:** A train passes 50 m long
platform in 14 seconds and a man standing on the platform in 10 seconds. Then
find

a.
Length of the train

b.
Speed of the train in
Km/hr

**Solution: C**arefully Read the
statement line by line.

**Step 1: A train passes 50m long platform in 14
seconds.**

It means length of platform and train is to be considered. But length
of train is not given in the statement. Let length of train is X meters.

**Step 2: a man standing
on the platform in 10 seconds.**

It means no length is to be considered for the man. Then length of
train will be considered only i.e. X meter.

·
X+50 meters length passes
in 14 seconds (from Step 1)

·
X meter length passes in 10 seconds (from Step 2)

Do the difference of above situations.

50 meters length passes in 4 seconds. This means this is that this
situation is left for train.

**a. Speed of the train can
be calculated as:**

Speed = Distance/Time

Speed of Train = 50 meter / 4 seconds = 50/4 m/s = (50/4) (18/5) =
36 Km/hr Ans.

**b. Length of the train can be calculated as:**

In 1 second train covers
50/4 meters (from speed as calculated above).

In 10 seconds it will
cover (50/4).10 = 125 meter. This is the required length of train in meters
i.e. 120 meters.

**TYPE-2 - ****Math Short Cut Tricks to solve Time and Distance Problems**

**Question 2:** A train passes two bridges of length 800m
& 400 m in 100 seconds and 60 seconds respectively. Then find

a.
Length of the train

b.
Speed of the train in
Km/hr

**Solution: C**arefully Read the
statement line by line.

**Step 1: A train passes two bridges of length
800 m & 400 m in 100 seconds and 60 seconds respectively **

It means length of platform and train is to be considered. But length
of train is not given in the statement. Let length of train is X meters.

·
X+800 meters length passes
in 100 seconds (from Step 1)

·
X+400 meter length passes
in 60 seconds (from Step 1)

Do the difference of above situations.

400 meters length passes in 40 seconds. This means this is that
this situation is left for train.

**a. Speed of the train can
be calculated as:**

Speed = Distance/Time

Speed of Train = 400 meter / 40 seconds = 10 m/s = (10) (18/5) =
36 Km/hr.

**b. Length of the train can be calculated as:**

In 1 second train covers
10 meters (from speed as calculated above).

In 60 seconds it will
cover 60 x 10 = 600 meter. But this is
the total length of train and platform which is of 400 meter. It means that
600-400=200 meter is the required length of train.