Math Short Cut Tricks to solve Time and Distance Problems - cutoffmarksresults.in

Math Short Cut Tricks to solve Time and Distance Problems - CRACK MATH-SCORE EXAM-TOP 7 TRICKS TO SOLVE TIME AND DISTANCE-FASTEST TRICK TO SOLVE MATH TIME AND DISTANCE PROBLEM-www.cutoffmarksresults.in
It is found that at least 1-2 questions are given to calculate train speed, length and time in SSC IBPS or other exam format. These questions are very easy to solve by using top 7 tricks.

These Math Short Cut Tricks to solve Time and Distance Problems help in getting cracking score in exams. Remember these top 7 trick to solve any question related to calculate Train speed, length and time in any of the competitive exam.
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Math Short Cut Tricks to solve Time and Distance Problems
Top 7 tricks to solve Train speed and length question which are given as follows:
1.      Average Speed = Total Distance/Total Time
2.      Trick for Train Questions:

1 Km/hr = (All Lengths in meters x 18)/ (Time in seconds x 5)
·         Let speed of Train in Km/hr is to be found.
·         Put all distances in ‘All Length in meters’ place (given for train or platform-Add all lengths in meter).
·         Put all time in ‘Time in second’ place (covert all time to seconds-Add all Time).
·         Put all values and calculate for answer.
3.      If a train is passing men, car, bus, pole etc. then only Length of the train in meter will be considered. It means no distance is taken for these objects. It means train passes and the length calculated is the length for train only.
4.      If the train passes bridge, tunnel, platform or another train, the distance will be added.
·         All Lengths in meters = Length of the train + Length of the platform
·         All Lengths in meters = Length of the train + Length of the Cave
·         All Lengths in meters = Length of the train + Length of the Flyover
·         Whenever two distance are provided in the question paper i.e. length of train, platform, cave, flyover etc., then add these lengths and convert it into meters if it is given in Kilometer, centimeter etc.
5.      When two train’s starts from same platform in same direction to destinations with two different speeds, then average speed will be subtraction between their speeds.
Let First train speed is x m/s and other y m/s, then average speed will be x-y.

6.      When two trains starts from same platform but in opposite direction, then average speed will be addition of their speeds.
Let First train speed is x m/s and other y m/s, then average speed will be x+y.
7.      Conversion:
·         1 Km/hr = 5/18 m/s (if higher value is need-Km/hr then multiply with lower value-5/18 to m/s).
·         1 m/s = 18/5 Km/hr(if lower value is need-m/s then multiply with higher value-18/5 to m/s).

HOW TO APPLY TRAIN TRICKS - Math Short Cut Tricks to solve Time and Distance Problems
TYPE-1
Question: A train passes 50 m long platform in 14 seconds and a man standing on the platform in 10 seconds. Then find
a.       Length of the train
b.      Speed of the train in Km/hr

Solution: Carefully Read the statement line by line.
Step 1: A train passes 50m long platform in 14 seconds.
It means length of platform and train is to be considered. But length of train is not given in the statement. Let length of train is X meters.
Step 2: a man standing on the platform in 10 seconds.
It means no length is to be considered for the man. Then length of train will be considered only i.e. X meter.

·         X+50 meters length passes in 14 seconds (from Step 1)
·         X meter length passes in 10 seconds (from Step 2)
Do the difference of above situations.
50 meters length passes in 4 seconds. This means this is that this situation is left for train.
a. Speed of the train can be calculated as:
Speed = Distance/Time
Speed of Train = 50 meter / 4 seconds = 50/4 m/s = (50/4) (18/5) = 36 Km/hr Ans.
b. Length of the train can be calculated as:
In 1 second train covers 50/4 meters (from speed as calculated above).
In 10 seconds it will cover (50/4).10 = 125 meter. This is the required length of train in meters i.e. 120 meters.
TYPE-2 - Math Short Cut Tricks to solve Time and Distance Problems
Question 2:  A train passes two bridges of length 800m & 400 m in 100 seconds and 60 seconds respectively. Then find
a.       Length of the train
b.      Speed of the train in Km/hr

Solution: Carefully Read the statement line by line.
Step 1: A train passes two bridges of length 800 m & 400 m in 100 seconds and 60 seconds respectively
It means length of platform and train is to be considered. But length of train is not given in the statement. Let length of train is X meters.
·         X+800 meters length passes in 100 seconds (from Step 1)
·         X+400 meter length passes in 60 seconds (from Step 1)
Do the difference of above situations.
400 meters length passes in 40 seconds. This means this is that this situation is left for train.
a. Speed of the train can be calculated as:
Speed = Distance/Time
Speed of Train = 400 meter / 40 seconds = 10 m/s = (10) (18/5) = 36 Km/hr.
b. Length of the train can be calculated as:
In 1 second train covers 10 meters (from speed as calculated above).
In 60 seconds it will cover 60 x 10 = 600 meter.  But this is the total length of train and platform which is of 400 meter. It means that 600-400=200 meter is the required length of train. 

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