Math Shortcut Tricks for Time & Distances for Bank, Railway exams

Math Shortcut Tricks for Time & Distances questions - Math Shortcuts to solve Time and Distance of Train, bus, car etc. for Bank, Railway exams: It is found that at least 2-3 questions are given to calculate TIME AND DISTANCE based questions in SSC IBPS or other exam format. These questions are very easy to solve by using SIMPLE TRICKS in 2-3 Seconds after reading statement of question.

Math Shortcut Tricks / formulae for Time & Distances questions

These SUPER FAST TRICKS helps in getting CUT-OFF score in exams. Use these tricks to solve NUMERICAL ABILIY section of SSC IBPS or other any other competitive exam.


SUPER FAST TRICKS are described as follows:

1.      Use LCM Method for calculation.
2.      Late & Late will be subtracted.
3.      Early & Early will be subtracted.
4.      Late & Early will be added.
5.      Stopped time/hr = Difference of speeds/ Speed without Stoppage
6.      When a person moves with two different speeds and takes the same time as more or less, then
Original Speed = (2 x Increase in speed x Decrease in Speed)/ difference between two speeds.
7.        SA/SB = √TB/TA
-------------------------------
Question 1:
A man goes to his office at a speed of 15 Km/hr & he is late by 20 minutes. Next day he goes at a speed of 10 KM/hr and still late by 30 minutes. Find the distance from the office to his home.
Solution: By Using Super Fast Trick (Rule 1-4)

Home to Office           (Speed)                        LCM               Early               Late
Day1                            15 Km/hr         2hr                               ---                    20 minutes
                                                                        30 KM
Next Day                     10 Km/hr         3hr                               ----                   30 minutes
                                                            3-2=1hrs                                  Total = 30-20 = 10 Minutes
                                                                 =60 minutes

With two different speeds the time difference is 1hr i.e. 60 Minutes-----1/6------------10minutes       
Thus the distance from house to office will be 30KM--------------------1/6-----------5KM Ans
----------------------------------------
Question 2:
A man goes to his office at a speed of 10 Km/hr & he is late by 25 minutes. Next day he goes at a speed of 12 KM/hr and reach early by 5 minutes. Find the distance from the office to his home.
Solution: By Using Super Fast Trick (Rule 1-4)

Home to Office            (Speed)      Efficiency  LCM               Early               Late
Day1                            10 Km/hr         6hr                               ---                    25 minutes
                                                                        60 KM
Next Day                     12 Km/hr         5hr                               5 minutes         ------
                                                            6-5=1hrs                                  Total = 25+5 = 30 Minutes
                                                                 =60 minutes

With two different speeds the time difference is 1hr i.e. 60 Minutes-----1/2------------30minutes       
Thus the distance from house to office will be 60KM--------------------1/2-----------30 KM Ans
-----------------------------------------
Question 3:
A Person travels a certain distance at an average speed of 80 Km/hr without any stoppage and covers the same distance at an average speed with stoppage. How many minutes per hour does he stop?
Solution: By Using Super Fast Tricks: (Rule 5)
Stopped time/hr     =          Difference of speeds/ Speed without Stoppage
                             
                                                =          (80-60)/80
                                                =          20/80 = ¼ hours
                                                = ¼ x 60 = 15minutes Ans
-----------------------------------------
Question 4:
A man covers a certain distance. When he moves 3 Km/hr faster then he would take 40 minutes less and when he moves 2 Km/hr slower then he would take 40 minutes more. Find the distance in Km & Find the original speed.
Solution: By Using Super Fast Trick:
Original Speed = (2 x Increase in speed x Decrease in Speed)/ difference between two speeds
                        = (2 x 3 x 2) / (3-2)
                        = 12/1= 12 Km/hr

Move                           (Speed)                          LCM               Early               Late
Move1                         15 Km/hr         2hr                               ---                    40 minutes
                                                                        30 KM
Move2                         10 Km/hr         3hr                               40 minutes       -----
                                                            3-2=1hrs                                  Total = 40+40 = 80 Minutes
                                                                 =60 minutes

With two different speeds the time difference is 1hr i.e. 60 Minutes-----4/3------------80minutes       
Thus the distance from house to office will be 30KM--------------------4/3-----------40 KM Ans

-----------------------------------------------
Question 5
Two trains A & B start from X and Y towards Y & X respectively. After meeting 1st train covers the remaining distance in 4hrs and 2nd covers the remaining distance in 9hrs. If the speed of 1st is 9Km/hr then find the speed of 2nd train.
Solution: By using Super Fast Tricks
Let SA is the speed of 1st train & SB is the speed of 2nd train.
Similarly TA is the speed of 1st train & TB is the speed of 2nd train.
Thus
SA/SB = √TB/TA
9 / SB = √9/4 = 3/2
SB = 6 Km/hr Ans

Do the practice till everyone can able to solve such questions in 2 seconds after reading statement of questions. –BEST OF LUCK-


Click here to download Super Fast Reasoning Tricks

AddToAny